Version: 2019.2
LanguageEnglish
  • C#

VideoPlayer.Prepare

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public void Prepare();

Description

Initiates playback engine preparation.

The preparation consists of reserving the resources needed for playback, and preloading some or all of the content to be played. After this is done, frames can be received immediately and all properties related to the source can be queried.

See Also: VideoPlayer.isPrepared.

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