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Launcher.LaunchFile

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public static method LaunchFile(folder: WSA.Folder, relativeFilePath: string, showWarning: bool): void;
public static void LaunchFile(WSA.Folder folder, string relativeFilePath, bool showWarning);

Parameters

folderFolder type where the file is located.
relativeFilePathRelative file path inside the specified folder.
showWarningShows user a warning that application will be switched.

Description

Launches the default app associated with specified file.

Note: if the application associated with file is the same as the one performing the launch, Windows won't open a new application, instead it will simply invoke OnActivated event in App.xaml.[cs/cpp] file.

Is something described here not working as you expect it to? It might be a Known Issue. Please check with the Issue Tracker at issuetracker.unity3d.com.

Copyright © 2020 Unity Technologies. Publication Date: 2020-06-05.
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